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An observer moves towards a stationary source of sound with a velocity one–fifth of velocity of sound. The percentage increase in apparent frequency is

a
5%
b
20%
c
Zero
d
0.5%

detailed solution

Correct option is B

na=V+V0Vn=V+V5Vn=65nna-nn=∆nn=15 ∆nn%=15×100=20%

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