First slide

Alternating Current and voltage

Question

A 280 ohm electric bulb is connected to 200V electric line. The peak value of current in the bulb will be

Moderate

A

About one ampere
B

Zero
C

About two ampere
D

About four ampere

Solution

$i_{rms} = \frac{200}{280} = \frac{5}{7} A .$ So $i_{0} = i_{rms} \times \sqrt{2} = \frac{5}{7} \times \sqrt{2} \approx 1 A .$

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