First slide

AC Circuits

Question

A 12 ohm resistor and a 0.21 henry inductor are connected in series to an ac source operating at 20 volts, 50 cycle/second. The phase angle between the current and the source voltage is (tan^-15.5 = 80⁰ approx)

Moderate

A

30°
B

40°
C

80°
D

90°

Solution

$tanφ = \frac{ωL}{R} = \frac{2 π \times 50 \times 0 .21}{12} = 5 .5 \Rightarrow φ = 80^{o}$

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