Questions
An oil drop having charge 2e is kept stationary between two parallel horizontal plates 2.0 cm apart when a potential difference of 12000 volts is applied between them. If the density of oil is 900 kg/m3, the radius of the drop will be
detailed solution
Correct option is B
In equilibrium QE=mg⇒Q⋅Vd=mg=43πr3ρg⇒2×1.6×10−19×120002×10−2=43πr3×900×10⇒r=1.7×10−6mTalk to our academic expert!
Similar Questions
In Millikan's oil drop experiment an oil drop carrying a charge Q is held stationary by a potential difference 2400 V between the plates. To keep a drop of half the radius stationary the potential difference had to be made 600 V. What is the charge on the second drop
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