Q.
An oil drop of radius 2 mm with density 3 gcm−3 is held stationary under a constant electric field 3.55×105Vm−1 in the Millikan’s oil experiment. What is the number of excess electrons that the oil drop will possess? Consider g=9.81 m/s2
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a
1.73×1010
b
4.8×1011
c
17.3×1010
d
17.3×1012
answer is A.
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Detailed Solution
Electric force is balanced by gravitational force. FE = FG ⇒ neE=mg ⇒n=mgeE=ρV×geE=3000×43π2×10-33×9.811.6×10-19×3.55×105 ⇒n=1.73×1010
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