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One of the circuits for the measurement of resistance by potentiometer is shown. The galvanometer is connected at point A and zero deflection is observed at length PJ = 30 cm. In second case the secondary cell is changed.

Take ES = 10 V and r=1  Ω in 1st reading and ES = 5 V and r=2  Ω in 2nd reading. In second case, the zero deflection is observed at length PJ = 10 cm. What is the resistance R (in ohm)?

a
1  Ω
b
2  Ω
c
3  Ω
d
4  Ω

detailed solution

Correct option is A

When there is no current through galvanometer, current through R isI=ESR+rPotential difference =IR=ESRR+rNow ESRR+r=KlFor first case:  10 RR+1 = K30                 ….(i)For second case:  5 RR+2 = K10          …..(ii)Dividing (i) and (ii), we get R = 1  Ω

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