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Q.

One of the circuits for the measurement of resistance by potentiometer is shown. The galvanometer is connected at point A and zero deflection is observed at length PJ = 30 cm. In second case the secondary cell is changed.Take ES = 10 V and r=1  Ω in 1st reading and ES = 5 V and r=2  Ω in 2nd reading. In second case, the zero deflection is observed at length PJ = 10 cm. What is the resistance R (in ohm)?

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a

1  Ω

b

2  Ω

c

3  Ω

d

4  Ω

answer is A.

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Detailed Solution

When there is no current through galvanometer, current through R isI=ESR+rPotential difference =IR=ESRR+rNow ESRR+r=KlFor first case:  10 RR+1 = K30                 ….(i)For second case:  5 RR+2 = K10          …..(ii)Dividing (i) and (ii), we get R = 1  Ω
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