One of the circuits for the measurement of resistance by potentiometer is shown. The galvanometer is connected at point A and zero deflection is observed at length PJ = 30 cm. In second case the secondary cell is changed.Take ES = 10 V and r=1 Ω in 1st reading and ES = 5 V and r=2 Ω in 2nd reading. In second case, the zero deflection is observed at length PJ = 10 cm. What is the resistance R (in ohm)?
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a
1 Ω
b
2 Ω
c
3 Ω
d
4 Ω
answer is A.
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Detailed Solution
When there is no current through galvanometer, current through R isI=ESR+rPotential difference =IR=ESRR+rNow ESRR+r=KlFor first case: 10 RR+1 = K30 ….(i)For second case: 5 RR+2 = K10 …..(ii)Dividing (i) and (ii), we get R = 1 Ω