One end of a conducting rod is maintained at temperature 50^oC and at the other end ice is melting at 0^oC. The rate of melting of ice is doubled if

Moderate

A

The temperature is made 200^oC and the area of cross-section of the rod is doubled.
B

The temperature is made 100^oC and length of the rod is made four times.
C

The area of cross-section of the rod is halved and length is doubled.
D

The temperature is made 100^oC and the area of cross-section and length both are doubled.

Solution

In steady state, $Q = \frac{KA . ∆ θ}{l} \Rightarrow Q \propto \frac{A . ∆ θ}{l}$
Rate of melting of ice is doubled when Q is doubled option-(4) only satisfies this condition.

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