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One end of a copper rod of length 1 .0 m and area of cross-section 10-3 m2 is immersed in boiling water and the other end in ice. If the coefficient of thermal conductivity of copper is 92 cal/m/s/°C and the latent heat of ice is 8 x 104 cal /kg, then the amount of ice which will melt in one minute is

a
9⋅2×10−3kg
b
8×10−3kg
c
6⋅9×10−3kg
d
5⋅4×10−3kg

detailed solution

Correct option is C

Q=KAΔTtd=mL 92×10−3×100×601=m×8×104Solving, we get m=6⋅9×10−3kg

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