Questions
One end of a long metallic wire of length L is tied to the ceiling. The other end is tied to mass less spring of spring constant.k. A mass m hangs freely from the free end of the spring, The area of cross-section and Young's modulus of the wire are A and Y respectively. If the mass is slightly pulled down and released, it will oscillate with a time period T equal to
detailed solution
Correct option is B
Let us beat the wire as a strin8. The force constant is given byk1= force extension =YAL ∵Y=FA×LΔL or FΔL=YAL The wire of force constant k1 and spring of force constant k are in series. The combined force constant k2, is given by k2=k1kk1+k=(YA/L)(k)(YA/L)+k=YAkYA+kL now T=2πmk2=2π(YA+kL)mYAk1/2Talk to our academic expert!
Similar Questions
The identical springs of constant ‘K’ are connected in series and parallel as shown in figure A mass M is suspended from them. The ratio of their frequencies of vertical oscillations will be
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