One end of a long metallic wire of length L is tied to the ceiling. The other end is tied to massless spring of spring constant K. A mass m hangs freely from the free end of the spring. The area of cross-section and Young's modulus of the wire are A and Y respectively. If the mass is slightly pulled down and released, it will oscillate with a time period T equal to
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
2πmK
b
2π(YA+KL)mYAK1/2
c
2πmYAKL
d
2πmLYA
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The wire may be treated as a string for which force constant k1=ForceExtension=YAL ∵Y=FA×LΔLSpring constant of the spring k2=KHence spring constant of the combination (series)keq=k1k2k1+k2=(YA/L)K(YA/L)+K=YAKYA+KL∵Time period T=2πmk=2π(YA+KL)mYAK1/2
Not sure what to do in the future? Don’t worry! We have a FREE career guidance session just for you!
One end of a long metallic wire of length L is tied to the ceiling. The other end is tied to massless spring of spring constant K. A mass m hangs freely from the free end of the spring. The area of cross-section and Young's modulus of the wire are A and Y respectively. If the mass is slightly pulled down and released, it will oscillate with a time period T equal to