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Q.

One end of a 1 m long cylinder is fixed and the other end is free. A 100 N-m torque is applied at the free end and the angle of twist of the free end is 0.5o. Then total elastic strain energy stored in the cylinder is

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a

0.486 J

b

1.244 J

c

0.436 J

d

2.36 J

answer is C.

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Detailed Solution

U=12Tθ=12×100×π180×0.5J=0.436 Joule
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