One end of a spring of force constant k is fixed to a vertical wall and the other to a block of mass m resting on a smooth horizontal surface. There is another wall at a distance $$x0$$ from the black. The spring is then compressed by $$2x0$$ and released. The time taken to strike the wall is

Question

One end of a spring of force constant k is fixed to a vertical wall and the other to a block of mass m resting on a smooth horizontal surface. There is another wall at a distance $$x0$$  from the black. The spring is then compressed by $$2x0$$  and released. The time taken to strike the wall is

Infinity Learn · Accepted Answer

The total time from A to $$CtAc=tAB+tBC=(T/4)+tBCwhere$$ T $$=$$ time period of oscillation of spring mass system tBC  can be obtained from,  $$BC=ABsin(2$$π$$/T)$$ tBCPutting $$BCAB=12$$  we obtain  $$tBC=T12$$⇒$$tAC=T4+T12=2$$$$π$$$$3mk$$.

One end of a spring of force constant k is fixed to a vertical wall and the other to a block of mass m resting on a smooth horizontal surface. There is another wall at a distance $x_{0}$ from the black. The spring is then compressed by $2 x_{0}$ and released. The time taken to strike the wall is

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One end of a spring of force constant k is fixed to a vertical wall and the other to a block of mass m resting on a smooth horizontal surface. There is another wall at a distance x0 from the black. The spring is then compressed by 2x0 and released. The time taken to strike the wall is

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One end of a spring of force constant k is fixed to a vertical wall and the other to a block of mass m resting on a smooth horizontal surface. There is another wall at a distance $x_{0}$ from the black. The spring is then compressed by $2 x_{0}$ and released. The time taken to strike the wall is