One end of a spring of force constant k is fixed to a vertical wall and the other to a block of mass m resting on a smooth horizontal surface. There is another wall at a distance x0 from the black. The spring is then compressed by 2x0 and released. The time taken to strike the wall is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
16πkm
b
km
c
2π3mk
d
π4km
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
The total time from A to CtAc=tAB+tBC=(T/4)+tBCwhere T = time period of oscillation of spring mass system tBC can be obtained from, BC=ABsin(2π/T) tBCPutting BCAB=12 we obtain tBC=T12⇒tAC=T4+T12=2π3mk.