First slide

Speed of wave

Question

One end of a steel pipe of length 660 m is struck a blow. A listener at the other end hears two sounds at an interval of 1 .89 second, one through the metal and the other through air. If velocity of sound in air is 330 m/s, then velocity in metal will be

Easy

A

2000m/s
B

3000 m/s
C

4000 m/s
D

6000 m/s

Solution

Time taken thorough metal,
$t_{m} = d / v_{m} T i m e t a k e n t h r o u g h a i r t_{a} = d / v_{a} \frac{d}{v_{a}} â \frac{d}{v_{m}} = 1 â 89 or \frac{660}{330} â \frac{660}{v_{m}} = 1 â 89 o r 2 â 1 â 89 = 660 / v_{m} o r v_{m} = 6000 m / s$

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