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One end of a uniform wire of length L and weight ω is attached rigidly to a point in roof and a weight ω1is suspended from its lower end. If S is the area of cross-section of the wire, the stress in the wire at a height of 3L4 from its lower end is

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a

ω1S

b

ω1+ω4S

c

ω1+3ω4s

d

ω1+ωs

answer is C.

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Detailed Solution

At length 3L4 from lower end, tension in the wire,T = suspended load + 34× weight of wire = ω1+3ω4∴ Stress =TS=ω1+3ω4S

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