One end of a uniform wire of length L and weight ω is attached rigidly to a point in roof and a weight ω1is suspended from its lower end. If S is the area of cross-section of the wire, the stress in the wire at a height of 3L4 from its lower end is
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a
ω1S
b
ω1+ω4S
c
ω1+3ω4s
d
ω1+ωs
answer is C.
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Detailed Solution
At length 3L4 from lower end, tension in the wire,T = suspended load + 34× weight of wire = ω1+3ω4∴ Stress =TS=ω1+3ω4S