First slide

Elastic Modulie

Question

One end of a uniform wire of length L and of weight W is attached rigidly to a point in the roof and a weight W, is suspended from its lower end. If S is the area of cross-section of the wire, the stress in the wire at height (3 L/ 4) from its lower end is

Easy

A

W₁/S
B

$\{W_{1} + (W / 4)\} S$
C

$(W_{1} + \frac{3 W}{4}) / S$
D

$(W_{1} + W) / S$

Solution

Force at a height 3L / 4 from its lower end
= weight suspended + weight of $(\frac{3}{4})$ of the chain
$\begin{array}{l} = W_{1} + (\frac{3 W}{4}) \\ Stress = (W_{1} + \frac{3 W}{4}) / S \end{array}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App