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Q.

One face CD of a brass cube ABCD having length of side 10 cm is fixed and a tangential force is applied on the free face A. As a result the angular displacement of the other face is 0.18o. If shear modulus of brass is 4×1010 N/m2, the elastic potential energy stored in the cube is π2≈10

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a

150 J

b

300 J

c

200 J

d

50 J

answer is C.

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Detailed Solution

Shear strain, θ=0.18o=π180×0.18rad=π1000rad∴ strain energy stored per unit volumeu=12ηθ2=12×4×1010×π10002 Jm3=2×1010×10106 Jm3=2×105 Jm3∴Total strain energy stored = volume x energy density =101003×2×105J=200 J

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