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One fourth length of a uniform rod of length 2l and mass m is placed on a horizontal table and the rod is held horizontally. The rod is released from rest. The normal reaction on the rod as soon as the rod is released will be

a
5mg27
b
4mg31
c
mg9
d
4mg19

detailed solution

Correct option is B

The torque applied by gravity about the edge O=τ=mg(3ℓ/4)⇒ I0α=34mg    ......(a) where I0=Ig+m3ℓ42=mℓ212+916mℓ2=mℓ2413+94I0=31mℓ248   ......(b) (a) and (b) yield, α=3mgℓ/431mℓ2/48⇒ α=144g124ℓ=36g31ℓ   ......(c)Newton's second law of motion:mg−N=ma   .....(d)Kinematics: a=3ℓ4α=36g31Using (d) and (e) we obtainN=mg−m27g31⇒N=4mg31

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