Questions
One fourth length of a uniform rod of length 2l and mass m is placed on a horizontal table and the rod is held horizontally. The rod is released from rest. The normal reaction on the rod as soon as the rod is released will be
detailed solution
Correct option is B
The torque applied by gravity about the edge O=τ=mg(3ℓ/4)⇒ I0α=34mg ......(a) where I0=Ig+m3ℓ42=mℓ212+916mℓ2=mℓ2413+94I0=31mℓ248 ......(b) (a) and (b) yield, α=3mgℓ/431mℓ2/48⇒ α=144g124ℓ=36g31ℓ ......(c)Newton's second law of motion:mg−N=ma .....(d)Kinematics: a=3ℓ4α=36g31Using (d) and (e) we obtainN=mg−m27g31⇒N=4mg31Talk to our academic expert!
Similar Questions
A uniform rood AB of length and mass is free to rotate about point A. The rod is released from rest in the horizontal position. Given that the moment of inertia of the rod about A is , the initial angular acceleration of the rod will be
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests