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A one meter long (both ends open) organ pipe is kept in a gas that has triple the density of air at STP. Assuming the speed of sound in air at S.T.P is 300 m/s . The frequency difference between the fundamental and second harmonic of this pipe is

a
105 Hz
b
86.60 Hz
c
100 Hz
d
109.02 Hz

detailed solution

Correct option is B

We know that speed of sound is given by VS=γPρ ∴ VgasVair=ρairρgas ⇒Vgas300=13 ⇒Vgas=3003 Now, Difference in frequency = n2−n1=Vgas2l=3003×2×1=86.60 Hz

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A tube of certain diameter and of length 48 cm is open at both ends. Its fundamental frequency of resonance is found to be 320 Hz. The velocity of sound in air is 320 m/s. One end of the tube is now closed, considering the effect of end correction, calculate the lowest frequency of resonance for the tube (in Hz). 


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