Questions
In one metre long open pipe what is the harmonic of resonance obtained with a tuning fork of frequency 480 Hz
detailed solution
Correct option is C
In case of open pipe, n=Nv2l where N = order of harmonics = order of mode of vibration ⇒N=n×2lv=480330×2×1=3 (Here v = 330 m/s)Talk to our academic expert!
Similar Questions
A tube of certain diameter and of length 48 cm is open at both ends. Its fundamental frequency of resonance is found to be 320 Hz. The velocity of sound in air is 320 m/s. One end of the tube is now closed, considering the effect of end correction, calculate the lowest frequency of resonance for the tube (in Hz).
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