Questions
One mole of diatomic gas is being heated in a closed tank from 300K up to 1000 K. During the process part of the molecules dissociate. At 1000 K the energy of the diatomic molecules are only half of that of the whole gas. By what factor has the gas pressure increased ? (The oscillation of the molecules are not to be taken in account.)
detailed solution
Correct option is A
Let x mole of the gas dissociate at 1000 K No. of mole of diatomic gas molecule =1-x No. of moles of monatomic gas molecules=2 x X Energy of diatomic molecules = 12(energy of monatomic molecule + energy of the diatomic molecule)Energy of diatomic molecules = energy of monatomic molecule1-x5R2= 2x3R2⇒5-5x =6x⇒x=511total no of moles now 1-x+2x=1+x =1+511=1611 pressure of a gas is directly proportional to no of moles and temperature soPfinalPinitial=n2n1T2T1=161111000300=16033Talk to our academic expert!
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For one-mole ideal gas, a process follows the relation where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?
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