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One mole of helium is adiabatically expanded from its initial state (Pi,Vi,Ti) to its final state (Pf,Vf,Tf) . The decrease in the internal energy associated with this expansion is equal to

a
CV(Ti−Tf)
b
CP(Ti−Tf)
c
12(CP+CV)(Ti−Tf)
d
(CP−CV)(Ti−Tf)

detailed solution

Correct option is A

ΔU=μCVΔT=1×CVTf−Ti=−CVTi−Tf⇒|ΔU|=CVTi−Tf

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