One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figureThe change in internal energy of the gas during the transition is
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a
20 kJ
b
-20 kJ
c
20 J
d
-12 kJ
answer is B.
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Detailed Solution
The change in intemal energy of the gas∆U = P2V2- P1V1γ-1 = 2×6-4×575-1 = -20 kJ