First slide

Change in internal energy

Question

One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure
The change in internal energy of the gas during the transition is

Moderate

A

20 kJ
B

-20 kJ
C

20 J
D

-12 kJ

Solution

The change in intemal energy of the gas
$∆ U = \frac{P_{2} V_{2} - P_{1} V_{1}}{γ - 1} = \frac{2 \times 6 - 4 \times 5}{\frac{7}{5} - 1} = - 20 kJ$

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