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Questions  

One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure.
 

The change in internal energy of the gas during the transition is :

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a
-20 kJ
b
20 J
c
-12 kJ
d
20 kJ

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detailed solution

Correct option is A

∆U=nCV∆T and T=PVnR So     ∆T=T2-T1=P2V2-P1V1nR So     ∆U=nRγ-1P2V2-P1V1nR=P2V2-P1V1γ-1 ⇒      ∆U=-8×1032/5=-20 kJ


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