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One mole of ideal gas expands isobarically to double its volume at 27°C. Then the work done by the gas is nearly

a
2760 cal
b
414 cal
c
1380 cal
d
600 cal

detailed solution

Correct option is D

If volume is doubled, temperature is also doubled at constant pressureW=PdV=nRdT =1×2×300 =600cal

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