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One mole of ideal gas goes through process  P=2V21+V2 then the change in temperature of gas when volume changes from v=1m3  to v=  2m3 is

a
−45RK
b
−52RK
c
2K
d
115RK

detailed solution

Correct option is D

ideal gas equation PV=nRT---(1)P = pressure; V = volume;n=number of moles;R=universal gas constantT=temperature absolutegiven P=2V21+V2;substitute in eqn(1)2V21+V2V=1×R×T∵n=12V31+V2R=T---(2)substitute V=1 in equation(2) (given)T1=2(1)31+(1)2R=22R=1R---(3)substitute V=2  (given)T2=2×231+22R=165R---(4)T2−T1=165R−1R=16-55R=115RK.

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Similar Questions

Statement 1 :   Spontaneous processes of nature are irreversible.

Statement 2 :    A quasi-static process is an infinitely slow process such that the system remains in thermal and mechanical equilibrium with the surroundings throughout

 


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