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One mole of an ideal gas at an initial temperature of T K does 6R. joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3, the final temperature of the gas will be
detailed solution
Correct option is D
work done in adiabatic process =dW=-dU=-nCvdT here Cv= 3R2 6R=-3R2dT dT=-4 final temperature T-4Talk to our academic expert!
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During an adiabatic process, the pressure of a gas is found to be proportional to the cube of its temperature. The ratio of for the gas is
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