One mole of an ideal gas at an initial temperature of T K does 6R. joules of work adiabatically. If the ratio of specific heats of this gas at constant pressure and at constant volume is 5/3, the final temperature of the gas will be

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T+2.4 K

T -2.4K

T+4K

T-4 K

answer is D.

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Detailed Solution

work done in adiabatic process =dW=-dU=-nCvdT here Cv= 3R2 6R=-3R2dT dT=-4 final temperature T-4

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