One mole of an ideal gas at temperature T1 expands according to the law PV2=a (constant). The work done by the gas till temperature of gas becomes T2 is :

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12R(T2−T1)

13R(T2−T1)

14R(T2−T1)

15R(T2−T1)

answer is B.

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Detailed Solution

W=∫V1V2PdV =∫V1V2aV2dV =a[V33]V1V2=a3(V23−V13) =13[P2V2−P1V1] =13[nRΔT]=13R(T2−T1)

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