One mole of an ideal monoatomic gas requires $$210$$ J heat to raise the temperature by $$10K$$, when heated at constant pressure. If the same gas is heated at constant volume to raise the temperature by $$10K$$ then heat required is

Question

Infinity Learn · Accepted Answer

amount of heat required to raise the temperature of n mole of gas through dT is at constant volume is $$QV=nCVdT$$ at constant pressure is $$QP=nCPdT$$ divide above two equations,  given number of moles n and change in temperature dT is same  $$QVQP=CVCP=35$$  ⇒$$QV=35$$ΔQP given $$QP=210$$ joule $$QV=35x210=126J=heat$$ required to raise the temperature of gas through $$10K$$, at constant volume

One mole of an ideal monoatomic gas requires 210 J heat to raise the temperature by 10K, when heated at constant pressure. If the same gas is heated at constant volume to raise the temperature by 10K then heat required is

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