Q.

One mole of an ideal monoatomic gas undergo a thermodynamic cyclic process ABCDA as shown in internal energy (U) and density (ρ) graph.The corresponding pressure (p) versus volume (V) graph is

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answer is 2.

(Detailed Solution Below)

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Detailed Solution

(b) AB and CD are Isothermal process while BC and DA are isochoric process. For AB, U constant and ρ increases. Constant U means constant temperature. From ideal gas equation.p=ρRTM ∴ ρ increases, p increases∴ ρ=mV It p increases, V decreasesAt constant temperature so PV = K isothermal processFor BC, U increases at constant density. Constant density, constant volume and if T increases (as U increases) pressure also increases. Similar for rest two processes.So, final p – V variation is

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