Q.
One mole of a monatomic ideal gas goes through a thermodynamics cycle, as shown in the volume versus temperature V−T diagram. The correct statement(s) is/are: [R is the gas constant]
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a
Work done in this thermodynamic cycle 1→2→3→4→1 is W=12RT0
b
The ratio of heat transfer during processes 1→2 and 2→3 is Q1→2Q2→3=53
c
The ratio of heat transfer during processes 1→2 and 3→4 is Q1→2Q3→4=12
d
The above thermodynamic cycle exhibits only isochoric and adiabatic processes.
answer is A.
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Detailed Solution
i W=Area=nRT02V0V0=12RT0(ii)Q12Q13=nCpΔTnCVΔT=53(iii)Q12Q34=nCpΔT1nCpΔT2=2 (iv) The above thermodynamic cycle exhibits only isochoric and isobaric processes.
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