One mole of a monatomic ideal gas undergoes an adiabatic expansion in which its volume becomes eight times its initial value. If the initial temperature of the gas is 100K and the universal gas constant R=8.0J mol−1K−1, the decrease in its internal energy, in joule, is .
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answer is 900.00.
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Detailed Solution
Vi=V VF=8V For adiabatic process {γ=53 for monoatomic process}T1V1γ−1=T2.V2γ−1⇒100V23=T28V23⇒T2=25KThus, Decrease in ΔU=nCvΔT=13R2100−25=12×75=900J