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One mole of mono atomic gas γ=53  is mixed with one mole of diatomic gas   γ=75. What will be the value of γ for the mixture.

a
1.45
b
1.4
c
1.54
d
1.5

detailed solution

Correct option is D

formula to find γmix is n1+n2γmix-1=n1γ1-1+n2γ2-1---(1)  here n1&n2=number of moles; γ1 &γ2= specific heat ratiogiven  n1=n2=1;γ1 =53;γ2=75  substitute given values in (1)1+1γmix-1=153−1+175−12γmix-1=123+1252γmix-1=32+52 ⇒2γmix-1=4γmix-1=12 ⇒γmix=1.5

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