First slide
Heat ;work and internal energy
Question

One mole of mono atomic gas γ=53  is mixed with one mole of diatomic gas   γ=75. What will be the value of γ for the mixture.

Moderate
Solution

  formula to find γmix is n1+n2γmix-1=n1γ1-1+n2γ2-1---(1)  here n1&n2=number of moles; γ1 &γ2= specific heat ratiogiven  n1=n2=1;γ1 =532=75  substitute given values in (1)1+1γmix-1=1531+17512γmix-1=123+1252γmix-1=32+52 2γmix-1=4γmix-1=12 γmix=1.5   

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