One mole of mono atomic gas γ=53 is mixed with one mole of diatomic gas γ=75. What will be the value of γ for the mixture.
1.45
1.4
1.54
1.5
formula to find γmix is n1+n2γmix-1=n1γ1-1+n2γ2-1---(1) here n1&n2=number of moles; γ1 &γ2= specific heat ratiogiven n1=n2=1;γ1 =53;γ2=75 substitute given values in (1)1+1γmix-1=153−1+175−12γmix-1=123+1252γmix-1=32+52 ⇒2γmix-1=4γmix-1=12 ⇒γmix=1.5