First slide

Heat ;work and internal energy

Question

One mole of mono atomic gas is mixed with three moles of diatomic gas. What is molecular specific heat of the mixture at constant volume?R=8.31 J/mole/K

Moderate

A

18.7 J/mole/K
B

1.87 J/mole/K
C

9.35 J/mole/K
D

4.67 J/mole/K

Solution

for mono atomic gas specific heat of gas at constant volume is $C_{v} = 3 R / 2$
For diatomic gas $C_{v} = 5 R / 2$
${(C_{v})}_{mix} = \frac{n_{1} C_{v_{1}} {+n}_{2} C_{v_{2}}}{{(n}_{1} {+n}_{2})} = \frac{1× \frac{3}{2} R+3× \frac{5}{2} R}{1+3} = \frac{9}{4} R = \frac{9}{4} \times 8.31 = 18.7 J / m o l e / K .$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App