Q.

One mole of mono atomic gas is mixed with three moles of diatomic gas. What is molecular specific heat of the mixture at constant volume?R=8.31 J/mole/K

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a

18.7 J/mole/K

b

1.87 J/mole/K

c

9.35 J/mole/K

d

4.67 J/mole/K

answer is A.

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Detailed Solution

for mono atomic gas  specific heat of gas at constant volume is Cv=3R/2For diatomic gas Cv=5R/2(Cv)mix=n1Cv1+n2Cv2(n1+n2)=1×32R+3×52R1+3=94R=94×8.31=18.7 J/mole/K.
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