Questions
One mole of a monoatomic gas is brought from state 'A' to state 'B' along path ACB. Temperature at 'A' is 'To' Heat absorbed along path ACB is equal To
detailed solution
Correct option is A
For ACP0V0T0=P02V0TC⇒TC=2T0For CBP02T0=2P0TB⇒TB=4T0For path ACBH=nCPTC−TA+nCVTB−TC=n52RT0+n32R2T0=112nRT0Talk to our academic expert!
Similar Questions
One mole of an ideal monoatomic gas undergoes a process ABC as shown in the indicator diagram. Heat supplied to the gas during the process is
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