One plate of a capacitor is fixed, and the other is connected to a spring as shown in Fig. Area of both the plates is A. In steady state (equilibrium), separation between the plates is 0.8d (spring was unstretched, and the distance between the plates was d when the capacitor was uncharged). The force constant of the spring is approximately
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a
12532ε0AE2d3
b
2ε0AE2d3
c
6ε0E2Ad2
d
ε0AE32d3
answer is A.
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Detailed Solution
F = Kx ⇒Q22Aε0=K(0.2d)⇒ε0A0.8dE22Αε0=0.2Kd⇒K = 4ε0AE2/d3