Questions
One plate of a capacitor is fixed, and the other is connected to a spring as shown in Fig. Area of both the plates is A. In steady state (equilibrium), separation between the plates is 0.8d (spring was unstretched, and the distance between the plates was d when the capacitor was uncharged). The force constant of the spring is approximately
detailed solution
Correct option is A
F = Kx ⇒Q22Aε0=K(0.2d)⇒ε0A0.8dE22Αε0=0.2Kd⇒K = 4ε0AE2/d3Talk to our academic expert!
Similar Questions
Two identical metal plates are given positive charges Q1 and Q2 (<Q1) respectively. If they are now brought close together to form a parallel plate capacitor with capacitance C, the potential difference between them is
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests