One quarter of the disc of mass m is removed. If r be the radius of the disc, the new moment of inertia is
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a
32m r2
b
m r22
c
38m r2
d
None of these.
answer is C.
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Detailed Solution
Momentum of inertia whole disc about an axis through centre of disc and perpendicular to its plane is I=12m r2 As one quarter of disc is removed, new mass,m'=34m ∴ 12(34m)r2=38m r2 .