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One quarter of the disc of mass m  is removed. If r  be the radius of the disc, the new moment of inertia is

a
32m r2
b
m r22
c
38m r2
d
None of these.

detailed solution

Correct option is C

Momentum of inertia whole disc about an axis through centre of disc and perpendicular to its plane is I=12m r2 As one quarter of disc is removed, new mass,m'=34m   ∴   12(34m)r2=38m r2 .

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