One quarter sector is cut from a uniform circular disc of radius R. This sector has mass M. It is made to rotate about a line perpendicular to its plane and passingthrough the centre of the original disc. Its moment of inertia about the axis of rotation is

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MR2/2

MR2/4

MR2/8

2MR2

answer is A.

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Detailed Solution

The moment of inertia of quarter disc about the centre is given byIC=14MR22, where M= mass of disc If M' be the mass of quarter disc, thenIc=14(4M)R22=MR22

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