First slide

Motion in a plane

Question

One of the rectangular components of velocity of 20 ms^–1 is 10 ms^–1. Find the other component.

Easy

A

$\large 10^{}\sqrt{3}$ ms^-1
B

$\large 20^{}\sqrt{3}^{^{^{}}}$ ms^-1
C

ms^-1
D

$35^{}\sqrt{3}$ ms^-1

Solution

If v_x and v_y be the magnitude of rectangular components of the velocity vector $\vec v$ , then $v_x^2 + v_y^2 = {v^2}\$
$\therefore {v_y} = \sqrt {{v^2} - v_x^2} = \sqrt {{{20}^2} - {{10}^2}} m/s = 10\sqrt 3 m/s$

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