First slide

Electromagnetic waves and its nature

Question

One requires $11 e V$ of energy to dissociate a carbon monoxide molecules into carbon and oxygen atoms. The minimum frequency of the appropriate electromagnetic radiation to achieve the dissociation lies in

Moderate

A

visible region
B

Infrared region
C

ultraviolet region
D

microwave region

Solution

Here it is given, the energy required to dissociate a carbon monoxide molecule into carbon and oxygen atoms is $E = 11 e V$ . We know that $E = h ϑ$ where $h = 6.62 \times 10^{- 34} J s$ and $ϑ$ is frequency
$\Rightarrow 11 e V = h ϑ \Rightarrow ϑ = \frac{11 \times 1.6 \times 10^{- 19}}{6.62 \times 10^{- 34}} = 2.65 \times 10^{15} H z$
This frequency radiation belongs to ultra violet region
*** when energy of the given photon is in electron volt then wave length will be $g i v e n b y λ = \frac{12432}{11} = 1130.18 \times 10^{- 10} m$
this wavelength of the photon is in ultra violet region because
$E = \frac{h c}{λ} s o λ = \frac{h c}{E} = \frac{12432}{E} i n A^{0}$
.

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