One of the strings at end Q is cut at t = 0 and the rod starts rotating about the other end P. Then

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At t = 0, angular acceleration of rod about P is 3g2L.

At t = 0, angular acceleration of rod about C.M. of rod is 3g2L.

At t = 0, acceleration of C.M. of rod is 3g4 in downward direction.

At t = 0, tension in the string at P is Mg4

answer is A.

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Detailed Solution

MgL2=ML23α∴ α=3g2L∴ acom=αL2=3g2LL2=3g4−T+Mg=M3g4∴ T=Mg4

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