One thousand small water drops of equal radii combine to form a big drop. The ratio of final surface energy to the total initial surface energy is
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a
1000 : 1
b
1 : 1000
c
10 : 1
d
1 : 10
answer is D.
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Detailed Solution
As volume remains constant therefore R = n13rsurface energy of one big dropsurface energy of n drop = 4πR2Tn×4πr2TR2nr2 = n23nr2 = 1n13 = 1(1000)13 = 110