First slide

Applications of SHM

Question

One-fourth length of a spring of force constant K is cut away. The force constant of the remaining spring will be

Easy

A

$\frac{3}{4} K$
B

$\frac{4}{3} K$
C

K
D

4 K

Solution

By using $K \propto \frac{1}{l}$
Since one fourth length is cut away so remaining length is $\frac{3}{4} th$ , hence k becomes $\frac{4}{3}$ times i.e., $k' = \frac{4}{3} k$ .

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