Standing waves

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An open organ pipe is suddenly closed with the result that the second overtone of the closed pipe is found to be higher in frequency by 100 Hz than the first overtone of the original pipe. The fundamental frequency of open pipe will be _____

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Solution

$\begin{array}{l} 5 . \frac{v}{4 l} - 4 . \frac{v}{4 l} = 100 \\ \frac{v}{4 l} = 100 \end{array}$
$∴$ Fundamental frequency = $2 . \frac{v}{4 l} = 200 Hz .$

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