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Q.

An open pipe of length 33 cm resonates to a frequency of 1000 Hz. The mode of vibration is: (velocity of sound = 330 m/s)

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a

Fundamental

b

The 2nd harmonic

c

The 3rd harmonic

d

The 4th harmonic

answer is B.

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Detailed Solution

As V2l = 330×1002×33 = 500 HzIn second harmonic frequency = Vl = 1000 Hz.
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