An open pipe is in resonance in its 2nd harmonic with tuning fork of frequency f1. Now it is closed at one end. If the frequency of the tuning fork is increased slowly fromf1 then again a resonance is obtained with a frequency f2 . If in this case the pipe vibrates nth harmonics then
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a
n=3,f2=34f1
b
n=3,f2=54f1
c
n=5,f2=54f1
d
n=5,f2=34f1
answer is C.
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Detailed Solution
Open pipe resonance frequency f1=2v2LClosed pipe resonance frequency f2=nv4Lf2=n4f1 (where n is odd and f2>f1 ) ∴ n=5