First slide

Stationary waves

Question

An open pipe resonates with a tuning fork of frequency 500 Hz. it is observed that two successive nodes are formed at distances 16 and 46 cm from the open end. The speed of sound in air in the pipe is

Moderate

A

230 m/s
B

300 m/s
C

320 m/s
D

360 m/s

Solution

Distance between two consecutive nodes
$= \frac{λ}{2} = 46 - 16 = 30 \Rightarrow λ = 60 cm = 0 .6 m$
$∴ v = nλ = 500 \times 0 .6 = 300 m / s$

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