First slide

Standing waves

Question

An open pipe is suddenly closed with the result that the second overtone of the closed pipe is observed to be higher in frequency by 100 Hz than the first overtone of the original pipe. The fundamental frequency of the open pipe will be

Moderate

A

100 Hz
B

300 Hz
C

150 Hz
D

200 Hz

Solution

$5 \times \frac{v}{4 l} - \frac{v}{l} = 100 or \frac{v}{l} (\frac{5}{4} - 1) = 100$
or $\frac{v}{4 l} = 100 or \frac{v}{2 l} = 200 or f = 200 Hz$

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