An open U-tube contains mercury, When 11.2 cm of water is poured into one of arms of the tube, how high does the mercury rise in the other arm from its initial level ?

When water is poured in the left arm, level of mercury in the right arm rises by x cm.Now  PA = PBPatm+11.2  ×  ρω × g=Patm+2x  ×  ρHg × g⇒   x  =  11.2  ×  12  ×  13.6  cm=0.41  cm