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Q.

An open U-tube contains mercury. When 11.2 cm of water is poured into one of the arms of the tube, how high does the mercury rise in the other arm from its initial level?

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a

0.56 cm

b

1.35 cm

c

0.41 cm

d

2.32 cm

answer is C.

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Detailed Solution

Let mercury rise in the other arm= xThen from pascal's lawPA=PB⇒11.2×ρwg=2xρHg ×gx=11.2×12×13.6=0.41 cm
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