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An open U-tube of uniform cross-section contains mercury when $54.4 c m$ of water is poured in to one limb of the tube, then the difference in levels of liquid of the two sides is ( $d_{w a t e r} = 1 g r m / c m^{3}$ , and $d_{H g} = 13.6 g m / c m^{3}$ )

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48.6

50.4

42.4

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detailed solution

Correct option is C

h1d1g=h2d2g54.4×1×g=h2×13.6×g⇒h2=54.413.6=4Difference=54.4–4=50.4

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An open U-tube of uniform cross-section contains mercury when 54.4 cm of water is poured in to one limb of the tube, then the difference in levels of liquid of the two sides is (dwater=1grm/cm3 , and dHg=13.6gm/cm3 )

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Ready to Test Your Skills?

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An open U-tube of uniform cross-section contains mercury when $54.4 c m$ of water is poured in to one limb of the tube, then the difference in levels of liquid of the two sides is ( $d_{w a t e r} = 1 g r m / c m^{3}$ , and $d_{H g} = 13.6 g m / c m^{3}$ )